320x-6000-x^2=0

Solution for 320x-6000-x^2=0 equation:

320x-6000-x^2=0

We add all the numbers together, and all the variables

-1x^2+320x-6000=0

a = -1; b = 320; c = -6000;
Δ = b2-4ac
Δ = 3202-4·(-1)·(-6000)
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{78400}=280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(320)-280}{2*-1}=\frac{-600}{-2}
=+300
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(320)+280}{2*-1}=\frac{-40}{-2}
=+20
$